Python: Find a string consisting of space-separated characters with given counts

Last update on April 17 2025 13:09:09 (UTC/GMT +8 hours)

Space-Separated Characters with Counts

Write a Python program to find a string consisting of space-separated characters with given counts.

Input: {'f': 1, 'o': 2}
Output:
f o o

Input: {'a': 1, 'b': 1, 'c': 1}
Output:
a b c

Visual Presentation:

Python: Find a string consisting of space-separated characters with given counts.

Sample Solution:

Python Code:

# License: https://bit.ly/3oLErEI

# Define a function named 'test' that takes a dictionary of character counts as input
def test(counts):
    # Use a nested loop to generate a string with characters repeated according to their counts
    return " ".join(c for c, i in counts.items() for _ in range(i))

# Example 1
strs1 = {"f": 1, "o": 2}
print("Original string:", strs1)
print("String consisting of space-separated characters with given counts:")
print(test(strs1))

# Example 2
strs2 = {"a": 1, "b": 1, "c": 1}
print("\nOriginal string:", strs2)
print("String consisting of space-separated characters with given counts:")
print(test(strs2))

Sample Output:

Original string: {'f': 1, 'o': 2}
String consisting of space-separated characters with given counts:
f o o

Original string: {'a': 1, 'b': 1, 'c': 1}
String consisting of space-separated characters with given counts:
a b c

Flowchart:

For more Practice: Solve these Related Problems:

Write a Python program to convert a dictionary mapping characters to counts into a space-separated string where each character is repeated as per its count.
Write a Python program to expand a dictionary of character frequencies into a list of characters and then join them with spaces.
Write a Python program to iterate over a dictionary and construct a string with each key repeated by its frequency, separated by spaces.
Write a Python program to use list comprehension to produce a string from a dictionary of counts, with each character occurring the specified number of times.

Go to:

Previous: Find a string contains a vowel between two consonants, in a given string.
Next: Reorder numbers in increasing/decreasing order based on whether the first plus last element is even/odd.

Python Code Editor :

Have another way to solve this solution? Contribute your code (and comments) through Disqus.