Python: Find the indices of two entries that show that the list is not in increasing order

Last update on May 30 2025 11:48:52 (UTC/GMT +8 hours)

Find Non-Increasing Indices

Write a Python program to find the indices of two entries that show that the list is not in increasing order. If there are no violations (they are increasing), return an empty list.

Input:
[1, 2, 3, 0, 4, 5, 6]
Output:
[2, 3]

Input:
[1, 2, 3, 4, 5, 6]
Output:
[]

Input:
[1, 2, 3, 4, 6, 5, 7]
Output:
[4, 5]

Input:
[-3, -2, -3, 0, 2, 3, 4]
Output:
[1, 2]

Visual Presentation:

Sample Solution:

Python Code:

# Define a function named 'test' that takes a list of numbers 'nums' as input
def test(nums):
    # Iterate over the indices of the list, except the last element
    for i in range(len(nums) - 1):
        # Check if the current element is greater than or equal to the next element
        if nums[i] >= nums[i + 1]:
            # Return the indices of the two entries that violate the increasing order
            return [i, i + 1]
    # If no violation is found, return an empty list
    return []

# Assign a specific list of numbers to the variable 'nums'
nums =  [1,2,3,0,4,5,6]
# Print a message indicating the original list of numbers
print("Original list:")
# Print the original list of numbers
print(nums)
# Print a message indicating the indices of two entries that violate the increasing order
print("Indices of two entries that show that the list is not in increasing order:")
# Print the result of the test function applied to 'nums'
print(test(nums))

# Assign another specific list of numbers to the variable 'nums'
nums =  [1,2,3,4,5,6]
# Print a message indicating the original list of numbers
print("\nOriginal list:")
# Print the original list of numbers
print(nums)
# Print a message indicating the indices of two entries that violate the increasing order
print("Indices of two entries that show that the list is not in increasing order:")
# Print the result of the test function applied to 'nums'
print(test(nums))

# Assign another specific list of numbers to the variable 'nums'
nums =  [1,2,3,4,6,5,7]
# Print a message indicating the original list of numbers
print("\nOriginal list:")
# Print the original list of numbers
print(nums)
# Print a message indicating the indices of two entries that violate the increasing order
print("Indices of two entries that show that the list is not in increasing order:")
# Print the result of the test function applied to 'nums'
print(test(nums))

# Assign another specific list of numbers to the variable 'nums'
nums =  [-3,-2,-3,0,2,3,4]
# Print a message indicating the original list of numbers
print("\nOriginal list:")
# Print the original list of numbers
print(nums)
# Print a message indicating the indices of two entries that violate the increasing order
print("Indices of two entries that show that the list is not in increasing order:")
# Print the result of the test function applied to 'nums'
print(test(nums))

Sample Output:

Original list:
[1, 2, 3, 0, 4, 5, 6]
Indices of two entries that show that the list is not in increasing order:
[2, 3]

Original list:
[1, 2, 3, 4, 5, 6]
Indices of two entries that show that the list is not in increasing order:
[]

Original list:
[1, 2, 3, 4, 6, 5, 7]
Indices of two entries that show that the list is not in increasing order:
[4, 5]

Original list:
[-3, -2, -3, 0, 2, 3, 4]
Indices of two entries that show that the list is not in increasing order:
[1, 2]

Flowchart:

For more Practice: Solve these Related Problems:

• Write a Python program to identify the first pair of consecutive indices where the list is not strictly increasing.
• Write a Python program to scan a list and return the indices where the current element is not greater than the previous one.
• Write a Python program to use a for-loop to find all pairs of indices indicating a drop in sequence value.
• Write a Python program to generate a list of index pairs showing where the list fails to be strictly increasing.

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Python Code Editor :

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