Python Exercises: Next number containing only distinct digits

Python Math: Exercise-91 with Solution

Write a Python program that accepts an integer number with distinct digits and displays the next number containing only distinct digits.

Sample Data:
12345) -> 12346
(99999) -> 102345
(100) -> 102

Sample Solution-1:

Python Code:

def test(n):
	n += 1
	if len(set(str(n))) == len(str(n)):
		return n
	return test(n)
n = 12345
print("Original number:", n)
print("Next number containing only distinct digits!") 
print(test(n))
n = 99999
print("Original number:", n)
print("Next number containing only distinct digits!") 
print(test(n))
n = 1
print("Original number:", n)
print("Next number containing only distinct digits!") 
print(test(n))
n = 100
print("Original number:", n)
print("Next number containing only distinct digits!") 
print(test(n))

Sample Output:

Original number: 12345
Next number containing only distinct digits!
12346
Original number: 99999
Next number containing only distinct digits!

Flowchart:

Sample Solution-2:

Python Code:

def test(n):    
    while True:
        n += 1
        x = sorted(str(n))
        temp = sorted(set(str(n)))
        if x == temp:
            return n
        
n = 12345
print("Original number:", n)
print("Next number containing only distinct digits!")
print(test(n))
n = 99999
print("Original number:", n)
print("Next number containing only distinct digits!")
print(test(n))
n = 1
print("Original number:", n)
print("Next number containing only distinct digits!")
print(test(n))
n = 100
print("Original number:", n)
print("Next number containing only distinct digits!")
print(test(n))

Sample Output:

Original number: 12345
Next number containing only distinct digits!
12346
Original number: 99999
Next number containing only distinct digits!
102345
Original number: 1
Next number containing only distinct digits!
2
Original number: 100
Next number containing only distinct digits!
102

Flowchart:

Python Code Editor:

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