w3resource

Python Math: Get the local and default precision

Python Math: Exercise-42 with Solution

Write a Python program to get the local and default precision.

Sample Solution:

Python Code:

import decimal
with decimal.localcontext() as context:
    context.prec = 2
    print('Local precision:', context.prec)
    print('22/7 =', (decimal.Decimal('22') / 7))

print()
print('Default precision:', decimal.getcontext().prec)
print('22 /7 =', (decimal.Decimal('22') / 7))

Sample Output:

Local precision: 2                                                                                            
22/7 = 3.1                                                                                                    
                                                                                                              
Default precision: 28                                                                                         
22 /7 = 3.142857142857142857142857143

Flowchart:

Flowchart: Get the local and default precision

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to round a specified number upwards towards infinity and down towards negative infinity of precision 4.
Next: Write a Python program to display the fraction instances of the string representation of a number.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Become a Patron!

Follow us on Facebook and Twitter for latest update.

It will be nice if you may share this link in any developer community or anywhere else, from where other developers may find this content. Thanks.

https://w3resource.com/python-exercises/math/python-math-exercise-42.php