Python Math: Find out, if the given number is abundant
Write a Python program to find out if the given number is abundant.
Note: In number theory, an abundant number or excessive number is a number for which the sum of its proper divisors is greater than the number itself. The integer 12 is the first abundant number. Its proper divisors are 1, 2, 3, 4 and 6 for a total of 16.
Sample Solution:
Python Code:
def is_abundant(n):
fctr_sum = sum([fctr for fctr in range(1, n) if n % fctr == 0])
return fctr_sum > n
print(is_abundant(12))
print(is_abundant(13))
Sample Output:
True False
Pictorial Presentation:
Flowchart:

Python Code Editor:
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous: Write a Python program to calculate the sum of all digits of the base to the specified power.
Next: Write a Python program to sum all amicable numbers from 1 to specified numbers.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
- Weekly Trends and Language Statistics
- Weekly Trends and Language Statistics