Python Math: Find the smallest multiple of the first n numbers
Python Math: Exercise-10 with Solution
Write a Python program to find the smallest multiple of the first n numbers. Also, display the factors.
Sample Solution:
Python Code:
def smallest_multiple(n):
if (n<=2):
return n
i = n * 2
factors = [number for number in range(n, 1, -1) if number * 2 > n]
print(factors)
while True:
for a in factors:
if i % a != 0:
i += n
break
if (a == factors[-1] and i % a == 0):
return i
print(smallest_multiple(13))
print(smallest_multiple(11))
print(smallest_multiple(2))
print(smallest_multiple(1))
Sample Output:
[13, 12, 11, 10, 9, 8, 7] 360360 [11, 10, 9, 8, 7, 6] 27720 2 1
Flowchart:
Python Code Editor:
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous: Write a Python program to calculate the discriminant value.
Next: Write a Python program to calculate the difference between the squared sum of first n natural numbers and the sum of squared first n natural numbers.(default value of number=2).
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
It will be nice if you may share this link in any developer community or anywhere else, from where other developers may find this content. Thanks.
https://w3resource.com/python-exercises/math/python-math-exercise-10.php
- Weekly Trends and Language Statistics
- Weekly Trends and Language Statistics