Python: Change the position of every n-th value with the (n+1)th in a list

Python List: Exercise - 38 with Solution

Write a Python program to change the position of every n-th value to the (n+1)th in a list.

Sample Solution:

Python Code:

# Import the 'zip_longest,' 'chain,' and 'tee' functions from the 'itertools' module
from itertools import zip_longest, chain, tee

# Define a function named 'replace2copy' that takes a list 'lst' as input and returns a new list with elements rearranged
def replace2copy(lst):
    # Use the 'tee' function to create two independent iterators from 'lst'
    lst1, lst2 = tee(iter(lst), 2)

    # Use 'zip_longest' to pair elements from 'lst' with an offset to create a new sequence
    # Chain the pairs together and convert them to a list
    return list(chain.from_iterable(zip_longest(lst[1::2], lst[::2])))

# Define a list 'n' containing numeric elements
n = [0, 1, 2, 3, 4, 5]

# Call the 'replace2copy' function with 'n' as the argument and print the result
print(replace2copy(n)) 

Sample Output:

[1, 0, 3, 2, 5, 4] 

Flowchart:

Python Code Editor:

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