Python: Find the numbers of a given string and store them in a list, display the numbers which are bigger than the length of the list in sorted form

Last update on December 31 2024 06:57:28 (UTC/GMT +8 hours)

Write a Python program to find the numbers in a given string and store them in a list. Afterward, display the numbers that are longer than the length of the list in sorted form. Use the lambda function to solve the problem.

Sample Solution:

Python Code :

# Define a string containing alphanumeric characters and numbers
str1 = "sdf 23 safs8 5 sdfsd8 sdfs 56 21sfs 20 5"

# Display the original string
print("Original string: ", str1)

# Split the string into a list of substrings separated by spaces
str_num = [i for i in str1.split(' ')]

# Calculate the length of the list of substrings
lenght = len(str_num)

# Extract and sort the numbers found within the substrings, converting them to integers
numbers = sorted([int(x) for x in str_num if x.isdigit()])

# Print the sorted numbers that are greater than the length of the list of substrings
print('Numbers in sorted form:')
for i in (filter(lambda x: x > lenght, numbers)):
    print(i, end=' ')

Sample Output:

Original string:  sdf 23 safs8 5 sdfsd8 sdfs 56 21sfs 20 5
Numbers in sorted form:
20 23 56

Python Code Editor:

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