Python: Index of the first element, which is greater than a specified element using itertools module
39. Index of First Greater Element
Write a Python program to get the index of the first element that is greater than a specified element using the itertools module.
Sample Solution:
Python Code:
from itertools import takewhile
def first_index(l1, n):
return len(list(takewhile(lambda x: x[1] <= n, enumerate(l1))))
nums = [12,45,23,67,78,90,100,76,38,62,73,29,83]
print("Original list:")
print(nums)
n = 73
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
n = 21
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
n = 80
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
n = 55
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
Sample Output:
Original list: [12, 45, 23, 67, 78, 90, 100, 76, 38, 62, 73, 29, 83] Index of the first element which is greater than 73 in the said list: 4 Index of the first element which is greater than 21 in the said list: 1 Index of the first element which is greater than 80 in the said list: 5 Index of the first element which is greater than 55 in the said list: 3
For more Practice: Solve these Related Problems:
- Write a Python program to iterate over a list and return the index of the first element that is greater than a specified target using itertools.takewhile.
- Write a Python program to create an iterator that scans through a list and finds the index of the first occurrence of an element exceeding a given value.
- Write a Python program to map a function over an iterable that returns the index of the first element satisfying a custom comparison condition.
- Write a Python program to use itertools.dropwhile to skip elements until one is found that is greater than a specified threshold, then output its index.
Python Code Editor:
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