w3resource

Python: Compute the sum of digits of each number of a given list of positive integers


34. Sum of Digits for Each Number

Write a Python program to compute the sum of digits of each number in a given list of positive integers.

Sample Solution:

Python Code:

from itertools import chain
def sum_of_digits(nums):
    return sum(int(y) for y in (chain(*[str(x) for x in nums])))

nums = [10,2,56]
print("Original tuple: ") 
print(nums)
print("Sum of digits of each number of the said list of integers:")
print(sum_of_digits(nums))

nums = [10,20,4,5,70]
print("\nOriginal tuple: ") 
print(nums)
print("Sum of digits of each number of the said list of integers:")
print(sum_of_digits(nums))

Sample Output:

Original tuple: 
[10, 2, 56]
Sum of digits of each number of the said list of integers:
14

Original tuple: 
[10, 20, 4, 5, 70]
Sum of digits of each number of the said list of integers:
19

For more Practice: Solve these Related Problems:

  • Write a Python program to compute the sum of digits for each number in a list and then filter out numbers with a digit sum below a certain threshold.
  • Write a Python program to use map to convert each positive integer into the sum of its digits and then return a list of these sums.
  • Write a Python program to generate a new list where each element is the sum of digits of the corresponding number from the original list, using a lambda.
  • Write a Python program to calculate the sum of digits for each number and then use filter to retain only numbers with an even digit sum.

Python Code Editor:


Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to find the pairs of maximum and minimum product from a given list. Use itertools module.

Next: Write a Python program to get all possible combinations of the elements of a given list using itertools module.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.