Python: Create non-repeated combinations of Cartesian product of three list

Last update on March 29 2025 13:03:27 (UTC/GMT +8 hours)

30. Non-repeated Cartesian Combinations

Write a Python program to create non-repeated combinations of the Cartesian product of a given list of four numbers.

Sample Solution:

import itertools as it
mums1 = [1, 2, 3, 4]
mums2 = [5, 6, 7, 8]
mums3 = [9, 10, 11, 12]
mums4 = [13, 14, 15, 16]
print("Original lists:")
print(mums1)
print(mums2)
print(mums3)
print(mums4)
print("\nSum of the specified range:")
for i in it.product([tuple(mums1)], it.permutations(mums2), it.permutations(mums3), it.permutations(mums4)):
    print(i)

Sample Output:

Original lists:
[1, 2, 3, 4]
[5, 6, 7, 8]
[9, 10, 11, 12]
[13, 14, 15, 16]

Sum of the specified range:
((1, 2, 3, 4), (5, 6, 7, 8), (9, 10, 11, 12), (13, 14, 15, 16))
((1, 2, 3, 4), (5, 6, 7, 8), (9, 10, 11, 12), (13, 14, 16, 15))

For more Practice: Solve these Related Problems:

• Write a Python program to compute the Cartesian product of a given list of four numbers and then filter out combinations with repeated digits.
• Write a Python program to generate non-repeated combinations from the Cartesian product of a list and then sort them in ascending order.
• Write a Python program to use itertools.product on a list of numbers and then remove tuples that contain duplicate elements.
• Write a Python program to generate the Cartesian product of a list and then filter out any combinations where the first and last elements are equal.

Python Code Editor:

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