Python: Sort a list of elements using Time sort
Python Search and Sorting : Exercise-21 with Solution
Write a Python program to sort a list of elements using Time sort.
Sample Solution:
Python Code:
# License https://bit.ly/2InTS3W
def binary_search(lst, item, start, end):
if start == end:
if lst[start] > item:
return start
else:
return start + 1
if start > end:
return start
mid = (start + end) // 2
if lst[mid] < item:
return binary_search(lst, item, mid + 1, end)
elif lst[mid] > item:
return binary_search(lst, item, start, mid - 1)
else:
return mid
def insertion_sort(lst):
length = len(lst)
for index in range(1, length):
value = lst[index]
pos = binary_search(lst, value, 0, index - 1)
lst = lst[:pos] + [value] + lst[pos:index] + lst[index+1:]
return lst
def merge(left, right):
if not left:
return right
if not right:
return left
if left[0] < right[0]:
return [left[0]] + merge(left[1:], right)
return [right[0]] + merge(left, right[1:])
def time_sort(lst):
runs, sorted_runs = [], []
length = len(lst)
new_run = [lst[0]]
sorted_array = []
for i in range(1, length):
if i == length - 1:
new_run.append(lst[i])
runs.append(new_run)
break
if lst[i] < lst[i - 1]:
if not new_run:
runs.append([lst[i - 1]])
new_run.append(lst[i])
else:
runs.append(new_run)
new_run = []
else:
new_run.append(lst[i])
for run in runs:
sorted_runs.append(insertion_sort(run))
for run in sorted_runs:
sorted_array = merge(sorted_array, run)
return sorted_array
user_input = input("Input numbers separated by a comma:\n").strip()
nums = [int(item) for item in user_input.split(',')]
print(time_sort(nums))
Sample Output:
Input numbers separated by a comma: 25, 45, 69, 79, 23 [23, 25, 45, 69, 79]
Flowchart:
Python Code Editor:
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