PostgreSQL Restricting and Sorting Data: Select all information of employees against some specific last name

Last update on February 07 2026 12:20:30 (UTC/GMT +8 hours)

11. Write a query to select all information of employees whose last name is either 'JONES' or 'BLAKE' or 'SCOTT' or 'KING' or 'FORD'.

Sample Solution:

Code:

SELECT * 
FROM employees 
WHERE last_name IN('Jones', 'Blake', 'Scott', 'King', 'Ford');

Sample table: employees

 +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
| EMPLOYEE_ID | FIRST_NAME  | LAST_NAME   | EMAIL    | PHONE_NUMBER       | HIRE_DATE  | JOB_ID     | SALARY   | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID |
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
|         100 | Steven      | King        | SKING    | 515.123.4567       | 1987-06-17 | AD_PRES    | 24000.00 |           0.00 |          0 |   		  90 |
|         101 | Neena       | Kochhar     | NKOCHHAR | 515.123.4568       | 1987-06-18 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         102 | Lex         | De Haan     | LDEHAAN  | 515.123.4569       | 1987-06-19 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         103 | Alexander   | Hunold      | AHUNOLD  | 590.423.4567       | 1987-06-20 | IT_PROG    |  9000.00 |           0.00 |        102 |            60 |
|         104 | Bruce       | Ernst       | BERNST   | 590.423.4568       | 1987-06-21 | IT_PROG    |  6000.00 |           0.00 |        103 |            60 |
|         105 | David       | Austin      | DAUSTIN  | 590.423.4569       | 1987-06-22 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         106 | Valli       | Pataballa   | VPATABAL | 590.423.4560       | 1987-06-23 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         107 | Diana       | Lorentz     | DLORENTZ | 590.423.5567       | 1987-06-24 | IT_PROG    |  4200.00 |           0.00 |        103 |            60 |
|         108 | Nancy       | Greenberg   | NGREENBE | 515.124.4569       | 1987-06-25 | FI_MGR     | 12000.00 |           0.00 |        101 |           100 |
..........
|         206 | William     | Gietz       | WGIETZ   | 515.123.8181       | 1987-10-01 | AC_ACCOUNT |  8300.00 |           0.00 |        205 |           110 |
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+

View the table

Output:

pg_exercises=# SELECT *
pg_exercises-# FROM employees
pg_exercises-# WHERE last_name IN('Jones', 'Blake', 'Scott', 'King', 'Ford');


 employee_id | first_name | last_name | email  |    phone_number    | hire_date  |  job_id  |  salary  | commission_pct | manager_id | department_id
-------------+------------+-----------+--------+--------------------+------------+----------+----------+----------------+------------+---------------
         100 | Steven     | King      | SKING  | 515.123.4567       | 1987-06-17 | AD_PRES  | 24000.00 |           0.00 |          0 |            90
         156 | Janette    | King      | JKING  | 011.44.1345.429268 | 1987-08-12 | SA_REP   | 10000.00 |           0.35 |        146 |            80
         195 | Vance      | Jones     | VJONES | 650.501.4876       | 1987-09-20 | SH_CLERK |  2800.00 |           0.00 |        123 |            50
(3 rows)

Relational Algebra Expression:

Relational Algebra Tree:

Go to:

PREV : Write a query to display the jobs/designations available in the employees table.
NEXT : PostgreSQL Aggregate Functions and Group By- Exercises, Practice, Solution

Practice Online

Have another way to solve this solution? Contribute your code (and comments) through Disqus.