PL/SQL Cursor Exercises: Show the uses of a virtual column in an explicit cursor query
PL/SQL Cursor: Exercise-34 with Solution
Write a PL/SQL block to show the uses of a virtual column in an explicit cursor query.
Sample Solution:
Table: employees
employee_id integer first_name varchar(25) last_name varchar(25) email archar(25) phone_number varchar(15) hire_date date job_id varchar(25) salary integer commission_pct decimal(5,2) manager_id integer department_id integer
PL/SQL Code:
DECLARE
CURSOR emp_cur IS
SELECT employee_id, first_name,
(salary * .05) sal_hike
FROM employees
WHERE job_id LIKE '%_PROG'
ORDER BY employee_id;
emp_sal_rec emp_cur%ROWTYPE;
BEGIN
OPEN emp_cur;
LOOP
FETCH emp_cur INTO emp_sal_rec;
EXIT WHEN emp_cur%NOTFOUND;
DBMS_OUTPUT.PUT_LINE (
'Salary increased for ' || emp_sal_rec.first_name ||
' is: ' || emp_sal_rec.sal_hike
);
END LOOP;
CLOSE emp_cur;
END;
/
Sample Output:
output SQL> / Salary increased for Alexander is: 450 Salary increased for Bruce is: 300 Salary increased for David is: 240 Salary increased for Valli is: 240 Salary increased for Diana is: 210 PL/SQL procedure successfully completed.
Flowchart:
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Previous: Write a PL/SQL block to show the uses of a variable in explicit cursor query, and the result set is affected with the value of the variable is incremented after every fetch.
Next: Write a PL/SQL block to display the employee ID, first name, job title and the start date of present job.
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