PHP Date Exercises : Add/subtract the number of days from a particular date

Last update on December 20 2024 10:18:38 (UTC/GMT +8 hours)

Write a PHP script to add/subtract the number of days from a particular date.

Sample Solution:

PHP Code:

<?php
$dt='2011-01-01'; // Assigning the date '2011-01-01' to the variable $dt.
echo 'Original date : '.$dt."\n"; // Outputting the original date.

$no_days = 40; // Setting the number of days to 40.
$bdate = strtotime("-".$no_days." days", strtotime($dt)); // Subtracting 40 days from the original date using strtotime function and storing the result in $bdate.
$adate = strtotime("+".$no_days." days", strtotime($dt)); // Adding 40 days to the original date using strtotime function and storing the result in $adate.

echo 'Before 40 days : '.date("Y-m-d", $bdate)."\n"; // Outputting the date 40 days before the original date.
echo 'After  40 days : '.date("Y-m-d", $adate)."\n"; // Outputting the date 40 days after the original date.
?>

Output:

Original date : 2011-01-01                                  
Before 40 days : 2010-11-22                                 
After  40 days : 2011-02-10

Explanation:

In the exercise above,

$dt='2011-01-01': Assign the date '2011-01-01' to the variable '$dt'.
echo 'Original date : '.$dt."\n";: Outputting the original date stored in '$dt'.
$no_days = the variable '$no_days' to 40.
$bdate = strtotime("-".$no_days." days", strtotime($dt));: Subtracting 40 days from the original date using "strtotime()" function and storing the result in '$bdate'.
$adate = strtotime("+".$no_days." days", strtotime($dt));: Adding 40 days to the original date using "strtotime()" function and storing the result in '$adate'.
echo 'Before 40 days : '.date("Y-m-d", $bdate)."\n";: Outputting the date 40 days before the original date.
echo 'After 40 days : '.date("Y-m-d", $adate)."\n";: Outputting the date 40 days after the original date.

Flowchart :

PHP Code Editor:

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