PHP function to check directory and create If not found

Last update on December 20 2024 10:21:14 (UTC/GMT +8 hours)

Write a PHP function to check if a directory exists and create it if it doesn't.

Sample Solution:

PHP Code :

<?php
function checkAndCreateDirectory($directory) {
    try {
        if (!is_dir($directory)) {
            if (!mkdir($directory, 0777, true))
            {
                throw new Exception("Error creating the directory.");
            }

            echo "
Directory created successfully.";
        }
        else
        {
            echo "
Directory already exists.";
        }
    }
    catch (Exception $e)
    {
        echo "An error occurred: " . $e->getMessage();
    }
}

// Usage:
$directory = "i:/data1";
checkAndCreateDirectory($directory);
$directory = "i:/data2";
checkAndCreateDirectory($directory);
?>

Sample Output:

Directory already exists.
Directory created successfully.

Explanation:

In the above exercise -

First, we define a function called checkAndCreateDirectory() that takes a directory path as input.

Inside the function, we use is_dir() to check if the directory already exists. If it doesn't exist, we use mkdir() to create the directory with 0777 permissions. The third argument "true" ensures that any necessary parent directories are also created. If creation succeeds, we display a success message. If there is an error creating the directory, we throw an exception with the error message "Error creating the directory."

If the directory already exists, we display the message "Directory already exists."

Flowchart:

PHP Code Editor:

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