PHP Exercises: Check if three given numbers are in strict increasing order

PHP Basic Algorithm: Exercise-48 with Solution

Write a PHP program to check if three given numbers are in strict increasing order, such as 4 7 15, or 45, 56, 67, but not 4 ,5, 8 or 6, 6, 8.However,if a fourth parameter is true, equality is allowed, such as 6, 6, 8 or 7, 7, 7.

Sample Solution:

PHP Code :

<?php
// Define a function that checks the order of $x, $y, and $z based on the value of $flag
function test($x, $y, $z, $flag)
{
    // If $flag is true, check if $x is less than or equal to $y and $y is less than or equal to $z
    // If $flag is false, check if $x is less than $y and $y is less than $z
    return $flag ? $x <= $y && $y <= $z : $x < $y && $y < $z;
}

// Test the function with different sets of numbers and flags
var_dump(test(1, 2, 3, false))."\n";
var_dump(test(1, 2, 3, true))."\n";
var_dump(test(10, 2, 30, false))."\n";
var_dump(test(10, 10, 30, true))."\n";
?>

Explanation:

• Function Definition:
• The function test checks the order of three numbers $x, $y, and $z based on the value of a boolean parameter $flag.
• Condition Checked:
• If $flag is true: The function checks if $x is less than or equal to $y and $y is less than or equal to $z ($x <= $y && $y <= $z).
• If $flag is false: The function checks if $x is strictly less than $y and $y is strictly less than $z ($x < $y && $y &lr $z).

Output:

bool(true)
bool(true)
bool(false)
bool(true)

Visual Presentation:

Flowchart:

PHP Code Editor:

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