PHP Exercises: Find the larger average value between the first and the second half of a given array of integers and minimum length is atleast 2

Last update on December 20 2024 10:26:05 (UTC/GMT +8 hours)

Write a PHP program to find the larger average value between the first and the second half of a given array of integers and minimum length is atleast 2. Assume that the second half begins at index (array length)/2.

Sample Solution:

PHP Code :

<?php
// Define a function named 'test' that takes an array of numbers as a parameter
function test($numbers)
{ 
    // Calculate the average of the first half of the array using the 'Average' function
    $firstHalf = Average($numbers, 0, sizeof($numbers) / 2);
    
    // Calculate the average of the second half of the array using the 'Average' function
    $secondHalf = Average($numbers, sizeof($numbers) / 2, sizeof($numbers));

    // Return the larger of the two averages
    return $firstHalf > $secondHalf ? $firstHalf : $secondHalf;
}  

// Define a function named 'Average' that calculates the average of a specified range within an array
function Average($num, $start, $end)
{
    // Initialize a variable to store the sum of elements in the specified range
    $sum = 0;

    // Iterate through the specified range and calculate the sum of elements
    for ($i = $start; $i < $end; $i++)
        $sum += $num[$i];

    // Return the average of the specified range
    return $sum / (sizeof($num) / 2);
}  

// Use the 'echo' statement to print the result of the 'test' function for different arrays
echo test([1, 2, 3, 4, 6, 8]) . "\n";
echo test([15, 2, 3, 4, 15, 11]) . "\n";
?>

Sample Output:

6
10

Flowchart:

PHP Code Editor:

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