MySQL Subquery Exercises: Find the name and salary of the employees whose salary is equal to the minimum salary for their job grade

MySQL Subquery: Exercise-6 with Solution

Write a MySQL query to find the name (first_name, last_name), and salary of the employees whose salary is equal to the minimum salary for their job grade.

Sample table: employees

+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
| EMPLOYEE_ID | FIRST_NAME  | LAST_NAME   | EMAIL    | PHONE_NUMBER       | HIRE_DATE  | JOB_ID     | SALARY   | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID |
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
|         100 | Steven      | King        | SKING    | 515.123.4567       | 1987-06-17 | AD_PRES    | 24000.00 |           0.00 |          0 |   		  90 |
|         101 | Neena       | Kochhar     | NKOCHHAR | 515.123.4568       | 1987-06-18 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         102 | Lex         | De Haan     | LDEHAAN  | 515.123.4569       | 1987-06-19 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         103 | Alexander   | Hunold      | AHUNOLD  | 590.423.4567       | 1987-06-20 | IT_PROG    |  9000.00 |           0.00 |        102 |            60 |
|         104 | Bruce       | Ernst       | BERNST   | 590.423.4568       | 1987-06-21 | IT_PROG    |  6000.00 |           0.00 |        103 |            60 |
|         105 | David       | Austin      | DAUSTIN  | 590.423.4569       | 1987-06-22 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         106 | Valli       | Pataballa   | VPATABAL | 590.423.4560       | 1987-06-23 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         107 | Diana       | Lorentz     | DLORENTZ | 590.423.5567       | 1987-06-24 | IT_PROG    |  4200.00 |           0.00 |        103 |            60 |
|         108 | Nancy       | Greenberg   | NGREENBE | 515.124.4569       | 1987-06-25 | FI_MGR     | 12000.00 |           0.00 |        101 |           100 |
.........
|         206 | William     | Gietz       | WGIETZ   | 515.123.8181       | 1987-10-01 | AC_ACCOUNT |  8300.00 |           0.00 |        205 |           110 |
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+

View the table

+------------+---------------------------------+------------+------------+
| JOB_ID     | JOB_TITLE                       | MIN_SALARY | MAX_SALARY |
+------------+---------------------------------+------------+------------+
| AD_PRES    | President                       |      20000 |      40000 |
| AD_VP      | Administration Vice President   |      15000 |      30000 |
| AD_ASST    | Administration Assistant        |       3000 |       6000 |
| FI_MGR     | Finance Manager                 |       8200 |      16000 |
| FI_ACCOUNT | Accountant                      |       4200 |       9000 |
| AC_MGR     | Accounting Manager              |       8200 |      16000 |
| AC_ACCOUNT | Public Accountant               |       4200 |       9000 |
| SA_MAN     | Sales Manager                   |      10000 |      20000 |
| SA_REP     | Sales Representative            |       6000 |      12000 |
| PU_MAN     | Purchasing Manager              |       8000 |      15000 |
.........
| PR_REP     | Public Relations Representative |       4500 |      10500 |
+------------+---------------------------------+------------+------------+

View the table

Code:

-- Selecting the first name, last name, and salary of employees 
SELECT first_name, last_name, salary 
-- Selecting data from the employees table
FROM employees 
-- Filtering the result set to include only employees whose salary matches the minimum salary defined for their job position
WHERE employees.salary = 
    -- Subquery to select the minimum salary for each job position from the jobs table
    (SELECT min_salary
    FROM jobs
    -- Matching the job_id of each employee with the job_id in the jobs table
    WHERE employees.job_id = jobs.job_id);

Explanation:

• This MySQL code selects the first name, last name, and salary of employees from a table named "employees".
• It filters the results to only include employees whose salary matches the minimum salary defined for their job position.
• This is achieved by using a subquery to select the minimum salary (min_salary) for each job position from the "jobs" table. The subquery is correlated to the outer query by matching the job_id of each employee with the job_id in the jobs table.

MySQL Subquery Syntax:

- The subquery (inner query) executes once before the main query (outer query) executes.
- The main query (outer query) use the subquery result.

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Structure of 'hr' database :

MySQL Code Editor:

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