Remove Distant Locations using Proximity Conditions
Delete Records Based on Spatial Criteria
Write a MySQL query to delete records from the Locations table where the distance from a given point exceeds 5000 units.
Solution:
-- Delete locations from the Locations table that are more than 5000 units away from a specified reference point.
DELETE FROM Locations
-- Use the ST_Distance function to calculate the distance between the 'location' column
-- and the reference point (created using ST_GeomFromText). Only rows where the distance
-- exceeds 5000 units will be deleted.
WHERE ST_Distance(location, ST_GeomFromText('POINT(-73.985130 40.758896)')) > 5000;
Explanation:
- Purpose of the Query:
- The goal is to remove records based on a spatial condition.
- This demonstrates filtering and deletion using spatial functions.
- Key Components:
- ST_Distance(location, ST_GeomFromText('POINT(...)')) > 5000 : Evaluates the distance condition for deletion.
- Real-World Application:
- Useful for maintaining a dataset with only nearby or relevant geographic entries.
Notes:
- Always review the spatial condition to avoid unintended data loss.
For more Practice: Solve these Related Problems:
- Write a MySQL query to delete records from "GeoLocations" where the distance from a given point exceeds 10000 units using ST_Distance.
- Write a MySQL query to remove entries from "Parks" if their spatial data lies outside a specified bounding box defined by spatial functions.
- Write a MySQL query to delete records from "Regions" where the calculated centroid is farther than a given distance from a reference point.
- Write a MySQL query to delete rows from "Shops" based on a spatial condition involving ST_Distance with a dynamically set threshold.
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Previous MySQL Exercise: Update a Spatial Data Point.
Next MySQL Exercise: Convert Spatial Data to Well-Known Text (WKT).
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