MongoDB Exercise - Find the highest score for each borough

Write a MongoDB query to find the highest score for each borough.

Structure of 'restaurants' collection :

{
  "address": {
     "building": "1007",
     "coord": [ -73.856077, 40.848447 ],
     "street": "Morris Park Ave",
     "zipcode": "10462"
  },
  "borough": "Bronx",
  "cuisine": "Bakery",
  "grades": [
     { "date": { "$date": 1393804800000 }, "grade": "A", "score": 2 },
     { "date": { "$date": 1378857600000 }, "grade": "A", "score": 6 },
     { "date": { "$date": 1358985600000 }, "grade": "A", "score": 10 },
     { "date": { "$date": 1322006400000 }, "grade": "A", "score": 9 },
     { "date": { "$date": 1299715200000 }, "grade": "B", "score": 14 }
  ],
  "name": "Morris Park Bake Shop",
  "restaurant_id": "30075445"
}

Query:

db.restaurants.aggregate([
{ $unwind: "$grades" },
{ $group: { 
      _id: { borough: "$borough" },
highestScore: { $max: "$grades.score" } 
    } 
  }
])

Output:

{ _id: { borough: 'Bronx' }, highestScore: 76 },
{ _id: { borough: 'Manhattan' }, highestScore: 131 },
{ _id: { borough: 'Brooklyn' }, highestScore: 77 },
{ _id: { borough: 'Queens' }, highestScore: 66 },
{ _id: { borough: 'Staten Island' }, highestScore: 58 }

Explanation:

The given query in MongoDB that finds a list of documents which includes the fields borough and highestScore where each document represents the highest score for a particular borough.

The $unwind creates a separate document for each element in the grades array. Then the $group operator groups the documents by borough and find the highest score for each group using the $max aggregation operator.

Note: This output is generated using MongoDB server version 3.6

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