JavaScript: Swap three numbers

JavaScript Math: Exercise-75 with Solution

Swap Three Numbers Without Third Variable

Write a JavaScript program to swap three numbers without a third variable.

Test Data:
(100, 200, 300) -> 300, 100, 200

Sample Solution:

JavaScript Code:

/**
 * Swaps the values of three variables using arithmetic operations.
 * @param {number} x - The first number.
 * @param {number} y - The second number.
 * @param {number} z - The third number.
 * @returns {Array} - An array containing the swapped values of x, y, and z.
 */
function test(x, y, z)
{
    // Calculate the sum of x, y, and z and assign it to x
    x = x + y + z;
    // Calculate y's new value using arithmetic operations
    y = x - (y + z);
    // Calculate z's new value using arithmetic operations
    z = x - (y + z);
    // Calculate x's new value using arithmetic operations
    x = x - (y + z);
    // Return an array containing the swapped values
    return [x, y, z];  
}
 
// Initialize variables x, y, and z
x = 100; 
y = 200; 
z = 300;

// Display the values before swapping
console.log("Before swapping:")
console.log("x = "+x);
console.log("y = "+y);
console.log("z = "+z);

// Call the test function to swap the values and store the result
result = test(x, y, z);

// Display the values after swapping
console.log("After swapping:");
console.log("x = "+result[0]);
console.log("y = "+result[1]);
console.log("z = "+result[2]);

Output:

Before swapping:
x = 100
y = 200
z = 300
After swapping:
x = 300
y = 100
z = 200

Flowchart:

Live Demo:

See the Pen javascript-math-exercise-75 by w3resource (@w3resource) on CodePen.

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