JavaScript: Compute the average and grade of the students

JavaScript Conditional Statement and loops: Exercise-6 with Solution

Student Grades Calculation

Write a JavaScript program that computes the average marks of the following students. Then, this average is used to determine the corresponding grade.

The grades are computed as follows:

Visual Presentation:

Sample Solution:

JavaScript Code:

// Array of students with their names and grades
var students = [['David', 80], ['Vinoth', 77], ['Divya', 88], ['Ishitha', 95], ['Thomas', 68]];

var Avgmarks = 0;

// Loop through the students array to calculate the total marks
for (var i = 0; i < students.length; i++) {
    Avgmarks += students[i][1];
    var avg = (Avgmarks / students.length);
}

// Calculate and log the average grade
console.log("Average grade: " + (Avgmarks) / students.length);

// Determine the grade based on the average
if (avg < 60) {
    console.log("Grade: F");
} else if (avg < 70) {
    console.log("Grade: D");
} else if (avg < 80) {
    console.log("Grade: C");
} else if (avg < 90) {
    console.log("Grade: B");
} else if (avg <= 100) {
    console.log("Grade: A");
} 

Output:

Average grade: 81.6
Grade : B

Flowchart:

Live Demo:

See the Pen javascript-conditional-statements-and-loops-exercise-6 by w3resource (@w3resource) on CodePen.

For more Practice: Solve these Related Problems:

• Write a JavaScript function that calculates the average marks of students and assigns grades using a switch statement.
• Write a JavaScript function that computes student grades from an array of marks and returns a summary object mapping grades to names.
• Write a JavaScript function that calculates the average mark and determines the corresponding grade without using if-else chains.
• Write a JavaScript function that validates student marks, computes the average, and assigns grades while handling missing scores gracefully.

Go to:

• JavaScript conditional statements and loops Exercises Home ↩
• JavaScript Exercises Home ↩

PREV : Odd or Even Loop.
NEXT : FizzBuzz.

Improve this sample solution and post your code through Disqus.