JavaScript: For loop that will iterate from 0 to 15 to find even and odd numbers
JavaScript Conditional Statement and loops: Exercise-5 with Solution
Odd or Even Loop
Write a JavaScript for loop that iterates from 0 to 15. For each iteration, it checks if the current number is odd or even, and displays a message on the screen.
Sample Output:
"0 is even"
"1 is odd"
"2 is even"
----------
----------
Calculate a Even Number:

Even Numbers between 1 to 100:

Calculate a Odd Number:

Odd Numbers between 1 to 100:

Sample Solution:
JavaScript Code:
// Using a for loop to iterate through numbers from 0 to 15
for (var x = 0; x <= 15; x++) {
// Checking if the current number is 0
if (x === 0) {
console.log(x + " is even");
}
// Checking if the current number is even
else if (x % 2 === 0) {
console.log(x + " is even");
}
// If the number is not 0 and not even, it is odd
else {
console.log(x + " is odd");
}
}
Output:
0 is even 1 is odd 2 is even 3 is odd 4 is even 5 is odd 6 is even 7 is odd 8 is even 9 is odd 10 is even 11 is odd 12 is even 13 is odd 14 is even 15 is odd
Flowchart:

Live Demo:
See the Pen javascript-conditional-statements-and-loops-exercise-5 by w3resource (@w3resource) on CodePen.
For more Practice: Solve these Related Problems:
- Write a JavaScript function that iterates from 0 to 15 and prints whether each number is odd or even using a ternary operator.
- Write a JavaScript function that determines odd or even status from 0 to 15 without using the modulo operator.
- Write a JavaScript function that checks numbers from 0 to 15 for odd or even status using bitwise operations.
- Write a JavaScript function that loops through 0 to 15, printing odd/even status while also identifying prime numbers.
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