JavaScript: For loop that will iterate from 0 to 15 to find even and odd numbers

JavaScript Conditional Statement and loops: Exercise-5 with Solution

Odd or Even Loop

Write a JavaScript for loop that iterates from 0 to 15. For each iteration, it checks if the current number is odd or even, and displays a message on the screen.

Sample Output:
"0 is even"
"1 is odd"
"2 is even"
----------
----------

Calculate a Even Number:

Even Numbers between 1 to 100:

Calculate a Odd Number:

Odd Numbers between 1 to 100:

Sample Solution:

JavaScript Code:

// Using a for loop to iterate through numbers from 0 to 15
for (var x = 0; x <= 15; x++) {
    // Checking if the current number is 0
    if (x === 0) {
        console.log(x + " is even");
    }
    // Checking if the current number is even
    else if (x % 2 === 0) {
        console.log(x + " is even");
    }
    // If the number is not 0 and not even, it is odd
    else {
        console.log(x + " is odd");
    }
} 

Output:

0 is even
1 is odd
2 is even
3 is odd
4 is even
5 is odd
6 is even
7 is odd
8 is even
9 is odd
10 is even
11 is odd
12 is even
13 is odd
14 is even
15 is odd

Flowchart:

Live Demo:

See the Pen javascript-conditional-statements-and-loops-exercise-5 by w3resource (@w3resource) on CodePen.

For more Practice: Solve these Related Problems:

• Write a JavaScript function that iterates from 0 to 15 and prints whether each number is odd or even using a ternary operator.
• Write a JavaScript function that determines odd or even status from 0 to 15 without using the modulo operator.
• Write a JavaScript function that checks numbers from 0 to 15 for odd or even status using bitwise operations.
• Write a JavaScript function that loops through 0 to 15, printing odd/even status while also identifying prime numbers.

Go to:

• JavaScript conditional statements and loops Exercises Home ↩
• JavaScript Exercises Home ↩

PREV : Largest of Five Numbers.
NEXT : Student Grades Calculation.

Improve this sample solution and post your code through Disqus.