JavaScript: Find the sign of product of three numbers

JavaScript Conditional Statement and loops: Exercise-2 with Solution

Write a JavaScript conditional statement to find the sign of the product of three numbers. Display an alert box with the specified sign.

Sample numbers : 3, -7, 2
Output : The sign is -

Sample Solution-1:

JavaScript Code:

// Assigning values to variables
var x = 3;
var y = -7;
var z = 2;

// Checking different conditions based on the signs of x, y, and z
if (x > 0 && y > 0 && z > 0) {
  alert("The sign is +");
} else if (x < 0 && y < 0 && z < 0) {
  console.log("The sign is -");
} else if (x > 0 && y < 0 && z < 0) {
  console.log("The sign is +");
} else if (x < 0 && y > 0 && z < 0) {
  console.log("The sign is +");
} else {
  console.log("The sign is -");
}

Output:

The sign is -

Flowchart:

Live Demo:

See the Pen javascript-conditional-statements-and-loops-exercise-2 by w3resource (@w3resource) on CodePen.

Sample Solution-2:

JavaScript Code:

// Assigning values to variables
var x = 3;
var y = -7;
var z = 2;

// Function to determine the sign based on the input value
function getSign(value) {
  if (value > 0) {
    return "+";
  } else if (value < 0) {
    return "-";
  } else {
    return "zero";
  }
}

// Checking the sign for each variable
var signX = getSign(x);
var signY = getSign(y);
var signZ = getSign(z);

// Determining the overall sign based on individual signs
var overallSign = (signX === signY && signY === signZ) ? "+" : "-";

// Displaying the result
console.log("The sign is " + overallSign); 

Output:

The sign is -

Flowchart:

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