JavaScript: Sum the multiples of 3 and 5 under 1000
JavaScript Conditional Statement and loops: Exercise-12 with Solution
Write a JavaScript program to sum 3 and 5 multiples under 1000.
Sample Solution
JavaScript Code:
// Variable to store the sum of numbers divisible by 3 or 5
var sum = 0;
// Loop through numbers from 0 to 999
for (var x = 0; x < 1000; x++) {
// Check if the current number is divisible by 3 or 5
if (x % 3 === 0 || x % 5 === 0) {
// Add the current number to the sum
sum += x;
}
}
// Output the final sum
console.log(sum);
Output:
233168
Flowchart:
Live Demo:
See the Pen javascript-conditional-statements-and-loops-exercise-12 by w3resource (@w3resource) on CodePen.
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