JavaScript: Compute the sum of absolute differences of consecutive numbers of a given array of integers

JavaScript Basic: Exercise-96 with Solution

Write a JavaScript program to compute the sum of the absolute differences of consecutive numbers in a given array of integers.

Visual Presentation:

Sample Solution:

JavaScript Code:

// Function to calculate the sum of adjacent differences in an array
function sum_adjacent_difference(arr) {
    var result = 0;  // Variable to store the result
    for (var i = 1; i < arr.length; i++) {
        // Add the absolute difference between adjacent elements to the result
        result += Math.abs(arr[i] - arr[i - 1]);
    }
    return result;  // Return the final sum
}

console.log(sum_adjacent_difference([1, 2, 3, 2, -5]));  // Example usage

Output:

10

Live Demo:

See the Pen javascript-basic-exercise-96 by w3resource (@w3resource) on CodePen.

Flowchart:

ES6 Version:

// Function to calculate the sum of absolute differences between adjacent elements in an array
const sum_adjacent_difference = (arr) => {
    let result = 0;  // Initialize the result variable to store the sum

    // Iterate through the array starting from the second element
    for (let i = 1; i < arr.length; i++) {
        result += Math.abs(arr[i] - arr[i - 1]);  // Add the absolute difference to the result
    }

    return result;  // Return the final sum
};

console.log(sum_adjacent_difference([1, 2, 3, 2, -5]));  // Example usage

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