JavaScript: Find the maximum possible sum of some of its k consecutive numbers of a specified array of positive integers

JavaScript Basic: Exercise-91 with Solution

Write a JavaScript program to find the maximum possible sum of some of its k consecutive numbers (numbers that follow each other in order) in a given array of positive integers.

Visual Presentation:

Sample Solution:

JavaScript Code:

function array_max_consecutive_sum(nums, k) {
  let result = 0;
  let temp_sum = 0;
  for (var i = 0; i < k - 1; i++) {
    temp_sum += nums[i];
  }
  for (var i = k - 1; i < nums.length; i++) {
    temp_sum += nums[i];
    if (temp_sum > result) {
      result = temp_sum;
    }
    temp_sum -= nums[i - k + 1];
  }
  return result;
}

console.log(array_max_consecutive_sum([1, 2, 3, 14, 5], 2))
console.log(array_max_consecutive_sum([2, 3, 5, 1, 6], 3))
console.log(array_max_consecutive_sum([9, 3, 5, 1, 7], 2))

Output:

19
12
12

Live Demo:

See the Pen javascript-basic-exercise-91 by w3resource (@w3resource) on CodePen.

Flowchart:

ES6 Version:

// Function to find the maximum consecutive sum of k elements in an array
const array_max_consecutive_sum = (nums, k) => {
  let result = 0;        // Initialize the result variable
  let temp_sum = 0;      // Initialize a variable to store the temporary sum

  // Calculate the initial temporary sum for the first k-1 elements
  for (let i = 0; i < k - 1; i++) {
    temp_sum += nums[i];
  }

  // Iterate through the array, updating the temporary sum and result
  for (let i = k - 1; i < nums.length; i++) {
    temp_sum += nums[i];
    
    // Update the result if the temporary sum is greater
    if (temp_sum > result) {
      result = temp_sum;
    }

    // Subtract the first element of the current k elements from the temporary sum
    temp_sum -= nums[i - k + 1];
  }

  // Return the final result
  return result;
};

// Example usage
console.log(array_max_consecutive_sum([1, 2, 3, 14, 5], 2));  
console.log(array_max_consecutive_sum([2, 3, 5, 1, 6], 3));  
console.log(array_max_consecutive_sum([9, 3, 5, 1, 7], 2));   

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