JavaScript: Test whether an array of integers of length 2 contains 1 or a 3

JavaScript Basic: Exercise-77 with Solution

Check if Array Contains 1 or 3

Write a JavaScript program to test whether an array of integers of length 2 contains 1 or 3.

Visual Presentation:

Sample Solution:

JavaScript Code:

// Function checks if the array 'nums' contains either 1 or 3
function contains13(nums) {
    // Check if 1 is present at any index or 3 is present at any index
    if (nums.indexOf(1) !== -1 || nums.indexOf(3) !== -1) {
        // Return true if either 1 or 3 is found
        return true;
    } else {
        // Return false if neither 1 nor 3 is found
        return false;
    }
}

// Example usage of the contains13 function
console.log(contains13([1, 5]));    // Should return true, as 1 is present
console.log(contains13([2, 3]));    // Should return true, as 3 is present
console.log(contains13([7, 5]));    // Should return false, as neither 1 nor 3 is present 

Output:

true
true
false

Live Demo:

See the Pen JavaScript - Create a new array taking the middle elements of the two arrays of integer and each length 3 - basic-ex-75 by w3resource (@w3resource) on CodePen.

Flowchart:

ES6 Version:

// ES6 version using arrow function
const contains13 = (nums) => {
  return nums.includes(1) || nums.includes(3);
};

// Example usage
console.log(contains13([1, 5]));
console.log(contains13([2, 3]));
console.log(contains13([7, 5]));

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