JavaScript: Reverse the elements of a given array of integers length 3

JavaScript Basic: Exercise-73 with Solution

Write a JavaScript program to reverse the elements of a given array of integers of length 3.

The program reverses the order of elements in an array of integers of length 3. It swaps the first and last elements, resulting in the array being in reverse order from its original state.

Visual Presentation:

Sample Solution:

JavaScript Code:

// Define a function named reverse3 that takes an array as a parameter
function reverse3(array) {
    // Use the map method to iterate over the array and reverse the order
    return array.map((element, idx, arr) => arr[(arr.length - 1) - idx]);
}

// Call the function with sample arguments and log the results to the console
console.log(reverse3([5, 4, 3]));  // Output: [3, 4, 5]
console.log(reverse3([1, 0, -1]));  // Output: [-1, 0, 1]
console.log(reverse3([2, 3, 1]));   // Output: [1, 3, 2] 

Output:

[3,4,5]
[-1,0,1]
[1,3,2]

Live Demo:

See the Pen JavaScript - Reverse the elements of a given array of integers length 3 - basic-ex-73 by w3resource (@w3resource) on CodePen.

Flowchart:

ES6 Version:

// Define a function named reverse3 that takes an array as a parameter
const reverse3 = (array) => array.map((element, idx, arr) => arr[(arr.length - 1) - idx]);

// Call the function with sample arguments and log the results to the console
console.log(reverse3([5, 4, 3]));  // Output: [3, 4, 5]
console.log(reverse3([1, 0, -1]));  // Output: [-1, 0, 1]
console.log(reverse3([2, 3, 1]));   // Output: [1, 3, 2]

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