JavaScript: Find a value which is nearest to 100 from two different given integer values

JavaScript Basic: Exercise-32 with Solution

Write a JavaScript program to find the closest value to 100 from two numerical values.

This JavaScript program compares two numerical values and determines which one is closest to 100. It calculates the absolute difference between each value and 100, then returns the value with the smaller difference.

Visual Presentation - 1:

Visual Presentation - 2:

Sample Solution:

JavaScript Code:

// Define a function named near_100 with parameters x and y
function near_100(x, y) {
  // Check if x is not equal to y
  if (x != y) {
    // Calculate the absolute difference between x and 100, store it in x1
    x1 = Math.abs(x - 100);

    // Calculate the absolute difference between y and 100, store it in y1
    y1 = Math.abs(y - 100);

    // Compare x1 and y1 to determine which value is closer to 100
    if (x1 < y1) {
      // Return x if x is closer to 100
      return x;
    }

    // Return y if y is closer to 100
    if (y1 < x1) {
      return y;
    }

    // Return 0 if x and y are equidistant from 100
    return 0;
  } else {
    // Return false if x is equal to y
    return false;
  }
}

// Log the result of calling near_100 with the arguments 90 and 89 to the console
console.log(near_100(90, 89));

// Log the result of calling near_100 with the arguments -90 and -89 to the console
console.log(near_100(-90, -89));

// Log the result of calling near_100 with the arguments 90 and 90 to the console
console.log(near_100(90, 90));

Output:

90
-89
false

Live Demo:

See the Pen JavaScript: value which is nearest to 100 - ex-32 by w3resource (@w3resource) on CodePen.

Flowchart:

ES6 Version:

// Define a function named near_100 with parameters x and y
const near_100 = (x, y) => {
  // Check if x is not equal to y
  if (x !== y) {
    // Calculate the absolute difference between x and 100, store it in x1
    const x1 = Math.abs(x - 100);

    // Calculate the absolute difference between y and 100, store it in y1
    const y1 = Math.abs(y - 100);

    // Compare x1 and y1 to determine which value is closer to 100
    if (x1 < y1) {
      // Return x if x is closer to 100
      return x;
    }

    // Return y if y is closer to 100
    if (y1 < x1) {
      return y;
    }

    // Return 0 if x and y are equidistant from 100
    return 0;
  } else {
    // Return false if x is equal to y
    return false;
  }
};

// Log the result of calling near_100 with the arguments 90 and 89 to the console
console.log(near_100(90, 89));

// Log the result of calling near_100 with the arguments -90 and -89 to the console
console.log(near_100(-90, -89));

// Log the result of calling near_100 with the arguments 90 and 90 to the console
console.log(near_100(90, 90));

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