JavaScript: Find whether the members of a given array of integers is a permutation of numbers from 1 to a given integer
JavaScript Basic: Exercise-123 with Solution
Write a JavaScript program to find out if the members of a given array of integers are a permutation of numbers from 1 to a given integer.
Visual Presentation:
Sample Solution:
JavaScript Code:
// Function to check if input array is a permutation of [1, 2, 3, ..., n]
function is_permutation(input_arr, n) {
// Loop through each element from 1 to n
for (var i = 0; i < n; i++) {
// Check if the current element is not found in the input array
if (input_arr.indexOf(i + 1) < 0) {
return false; // If not found, it's not a permutation
}
}
return true; // If all elements are found, it's a permutation
}
// Test cases
console.log(is_permutation([1, 2, 3, 4, 5], 5)); // Output: true (permutation of [1, 2, 3, 4, 5])
console.log(is_permutation([1, 2, 3, 5], 5)); // Output: false (not a permutation of [1, 2, 3, 4, 5])
Output:
true false
Live Demo:
See the Pen javascript-basic-exercise-123 by w3resource (@w3resource) on CodePen.
Flowchart:
ES6 Version:
// Function to check if input array is a permutation of [1, 2, 3, ..., n]
const is_permutation = (input_arr, n) => {
// Loop through each element from 1 to n
for (let i = 0; i < n; i++) {
// Check if the current element is not found in the input array
if (input_arr.indexOf(i + 1) < 0) {
return false; // If not found, it's not a permutation
}
}
return true; // If all elements are found, it's a permutation
}
// Test cases
console.log(is_permutation([1, 2, 3, 4, 5], 5)); // Output: true (permutation of [1, 2, 3, 4, 5])
console.log(is_permutation([1, 2, 3, 5], 5)); // Output: false (not a permutation of [1, 2, 3, 4, 5])
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