JavaScript: Third smallest number of an array of numbers

JavaScript Array: Exercise-49 with Solution

Write a JavaScript program that takes an array of numbers and returns the third smallest number.

Test Data:

(2,3,5,7,1) -> 3
(2,3,0,5,7,8,-2,-4) -> 0

Sample Solution:

JavaScript Code :

// Function to find the third smallest number in an array
function test(arr_nums) {
  // Sort the array in descending order using the compare function (y - x)
  // and return the third element (index 2) from the sorted array
  return arr_nums.sort((x, y) => y - x)[arr_nums.length - 3];
}

// Test the function with an array of numbers
nums = [2, 3, 5, 7, 1];
console.log("Original array of numbers: " + nums);
console.log("Third smallest number of the said array of numbers: " + test(nums));

// Test the function with another array of numbers
nums = [2, 3, 0, 5, 7, 8, -2, -4];
console.log("Original array of numbers: " + nums);
console.log("Third smallest number of the said array of numbers: " + test(nums));

Output:

Original array of numbers: 2,3,5,7,1
Third smallest number of the said array of numbers: 3
Original array of numbers: 2,3,0,5,7,8,-2,-4
Third smallest number of the said array of numbers: 0

Flowchart :

Live Demo :

See the Pen javascript-array-exercise-49 by w3resource (@w3resource) on CodePen.

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