JavaScript: Perform stable sorting of an array, preserving the initial indexes of items when their values are the same

JavaScript fundamental (ES6 Syntax): Exercise-137 with Solution

Write a JavaScript program to perform stable sorting of an array, preserving the initial indexes of items when their values are the same. Returns a new array instead of mutating the original array.

• Use Array.prototype.map() to pair each element of the input array with its corresponding index.
• Use Array.prototype.sort() and a compare function to sort the list, preserving their initial order if the items compared are equal.
• Use Array.prototype.map() to convert back to the initial array items.
• Does not mutate the original array, but returns a new array instead.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2

// Define the 'stableSort' function.
const stableSort = (arr, compare) =>
  arr
    .map((item, index) => ({ item, index })) // Map each item to an object containing the item and its index.
    .sort((a, b) => compare(a.item, b.item) || a.index - b.index) // Sort based on the comparison function and the original indices.
    .map(({ item }) => item); // Extract the sorted items from the objects and return them as an array.

// Test the 'stableSort' function with an array and a comparison function.
const arr = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
console.log(stableSort(arr, () => 0)); // Output: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Output:

[0,1,2,3,4,5,6,7,8,9,10]

Flowchart:

Live Demo:

See the Pen javascript-basic-exercise-137-1 by w3resource (@w3resource) on CodePen.

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