JavaScript: Get the sum of the powers of all the numbers from start to end

JavaScript fundamental (ES6 Syntax): Exercise-135 with Solution

Sum of Powers in Range

Write a JavaScript program to get the sum of the powers of all the numbers from start to end (both inclusive).

• Use Array.prototype.fill() to create an array of all the numbers in the target range.
• Use Array.prototype.map() and the exponent operator (**) to raise them to power and Array.prototype.reduce() to add them together.
• Omit the second argument, power, to use a default power of 2.
• Omit the third argument, start, to use a default starting value of 1.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2

// Define the 'sumPower' function.
const sumPower = (end, power = 2, start = 1) =>
  // Create an array from 'start' to 'end', apply the power operation, and then sum the elements.
  Array(end + 1 - start)
    .fill(0) // Fill the array with zeros.
    .map((x, i) => (i + start) ** power) // Apply the power operation to each element.
    .reduce((a, b) => a + b, 0); // Sum all the elements.

// Test the 'sumPower' function with various arguments.
console.log(sumPower(10)); // Output: 385 (1^2 + 2^2 + ... + 10^2)
console.log(sumPower(10, 3)); // Output: 3025 (1^3 + 2^3 + ... + 10^3)
console.log(sumPower(10, 3, 5)); // Output: 2925 (5^3 + 6^3 + ... + 10^3)

Output:

385
3025
2925

Visual Presentation:

Flowchart:

Live Demo:

For more Practice: Solve these Related Problems:

• Write a JavaScript program that calculates the sum of the k-th powers of all integers between two given numbers.
• Write a JavaScript function that iterates from start to end and sums up each number raised to a specified power.
• Write a JavaScript program that uses a loop or reduce() to compute the sum of powers for a range of integers.

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