Java: Compare two strings lexicographically, ignoring case differences

Last update on December 21 2024 10:02:54 (UTC/GMT +8 hours)

Write a Java program to compare two strings lexicographically, ignoring case differences.

Visual Presentation:

Sample Solution:

Java Code:

// Define a public class named Exercise6.
public class Exercise6 {
    // Define the main method.
    public static void main(String[] args) {
        // Declare and initialize two string variables, str1 and str2.
        String str1 = "This is exercise 1";
        String str2 = "This is Exercise 1";
        
        // Print the first string.
        System.out.println("String 1: " + str1);
        // Print the second string.
        System.out.println("String 2: " + str2); 
       
        // Compare the two strings ignoring case sensitivity and get the result of the comparison.
        int result = str1.compareToIgnoreCase(str2);

        // Display the results of the comparison.
        if (result < 0) {
            // If str1 (ignoring case) is less than str2 (ignoring case).
            System.out.println("\"" + str1 + "\"" +
                " is less than " +
                "\"" + str2 + "\"");
        } else if (result == 0) {
            // If str1 (ignoring case) is equal to str2 (ignoring case).
            System.out.println("\"" + str1 + "\"" +
                " is equal to " +
                "\"" + str2 + "\"");
        } else { // if (result > 0)
            // If str1 (ignoring case) is greater than str2 (ignoring case).
            System.out.println("\"" + str1 + "\"" +
                " is greater than " +
                "\"" + str2 + "\"");
        }
    }
}

Sample Output:

String 1: This is exercise 1                                                                                  
String 2: This is Exercise 1                                                                                  
"This is exercise 1" is equal to "This is Exercise 1"

Flowchart:

Java Code Editor:

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