Java: Compare two strings lexicographically

Last update on December 21 2024 10:02:48 (UTC/GMT +8 hours)

Write a Java program to compare two strings lexicographically.
Two strings are lexicographically equal if they are the same length and contain the same characters in the same positions.

Sample Solution:

Java Code:

// Define a public class named Exercise5.
public class Exercise5 {
    // Define the main method.
    public static void main(String[] args) {
        // Declare and initialize two string variables.
        String str1 = "This is Exercise 1";
        String str2 = "This is Exercise 2";
        
        // Print the first string.
        System.out.println("String 1: " + str1);
        // Print the second string.
        System.out.println("String 2: " + str2); 
       
        // Compare the two strings and get the comparison result.
        int result = str1.compareTo(str2);

        // Display the results of the comparison.
        if (result < 0) {
            // If the result is less than 0, print that the first string is less than the second.
            System.out.println("\"" + str1 + "\"" +
                " is less than " +
                "\"" + str2 + "\"");
        } else if (result == 0) {
            // If the result is 0, print that the first string is equal to the second.
            System.out.println("\"" + str1 + "\"" +
                " is equal to " +
                "\"" + str2 + "\"");
        } else { // if (result > 0)
            // If the result is greater than 0, print that the first string is greater than the second.
            System.out.println("\"" + str1 + "\"" +
                " is greater than " +
                "\"" + str2 + "\"");
        }
    }
}

Sample Output:

String 1: This is Exercise 1                                                                                  
String 2: This is Exercise 2                                                                                  
"This is Exercise 1" is less than "This is Exercise 2" 

Flowchart:

Java Code Editor:

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