Java: Find the second most frequent character in a given string
Java String: Exercise-34 with Solution
Write a Java program to find the second most frequent character in a given string.
Visual Presentation:
Sample Solution:
Java Code:
// Import necessary Java utilities.
import java.util.*;
// Define a class named Main.
public class Main {
// Define a constant representing the number of characters (ASCII).
static final int NOOFCHARS = 256;
// Define a method to find the second most frequent character in a string.
static char get2ndMostFreq(String str1) {
// Create an array to count occurrences of each character in the string.
int[] ctr = new int[NOOFCHARS];
int i;
// Count occurrences of each character in the string.
for (i = 0; i < str1.length(); i++) {
(ctr[str1.charAt(i)])++;
}
// Variables to store indices of the first and second most frequent characters.
int ctr_first = 0, ctr_second = 0;
for (i = 0; i < NOOFCHARS; i++) {
if (ctr[i] > ctr[ctr_first]) {
ctr_second = ctr_first;
ctr_first = i;
} else if (ctr[i] > ctr[ctr_second] && ctr[i] != ctr[ctr_first]) {
ctr_second = i;
}
}
// Return the second most frequent character.
return (char) ctr_second;
}
// The main method to execute the code.
public static void main(String args[]) {
// Define the input string.
String str1 = "successes";
System.out.println("The given string is: " + str1);
// Get the second most frequent character from the input string.
char res = get2ndMostFreq(str1);
// Display the result.
if (res != '\0') {
System.out.println("The second most frequent char in the string is: " + res);
} else {
System.out.println("No second most frequent character found in the string.");
}
}
}
Sample Output:
The given string is: successes The second most frequent char in the string is: c
Flowchart:
Java Code Editor:
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