Java: Find a specified element in a given array of elements using Ternary search
Java Search: Exercise-6 with Solution
Write a Java program to find a specified element in a given array of elements using Ternary search.
From Wikipedia, a ternary search algorithm is a technique in computer science for finding the minimum or maximum of a unimodal function. A ternary search determines either that the minimum or maximum cannot be in the first third of the domain or that it cannot be in the last third of the domain, then repeats on the remaining two thirds. A ternary search is an example of a divide and conquer algorithm.
Sample Solution:
Java Code:
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int[] nums = new int[]{0,1,2,3,5,7,9,12,15,17,18,21,25,32,52,54,75,89,90,93,97,104,120};
System.out.println("Original array:");
System.out.println(Arrays.toString(nums));
System.out.println("Input an element to search:");
int val = scan.nextInt();
int position = ternary_search(nums, val, 0, nums.length-1);
if(position == -1)
System.out.println("\n" +val+ " Element not found");
else
System.out.println("\n"+ val +" element found at position "+ position);
}
static int ternary_search(int[] nums, int val, int first_element, int last_element)
{
if(first_element > last_element)
{
return -1;
}
int mid1_element = first_element + (last_element - first_element) / 3;
int mid2_element = first_element + 2*(last_element - first_element) / 3;
if(val == nums[mid1_element])
{
return mid1_element;
}
else if(val == nums[mid2_element])
{
return mid2_element;
}
else if(val > nums[mid1_element])
{
first_element = mid1_element+1;
}
else if(val < nums[mid2_element])
{
last_element = mid2_element-1;
}
return ternary_search(nums, val, first_element, last_element);
}
}
Sample Output:
Original array: [0, 1, 2, 3, 5, 7, 9, 12, 15, 17, 18, 21, 25, 32, 52, 54, 75, 89, 90, 93, 97, 104, 120] Input an element to search: 25 25 element found at position 12
Flowchart:
Java Code Editor:
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