Java: Reverse the words of length higher than 3 in a given string
Write a Java program to reverse words longer than 3 in a given string.
Sample Solution:
Java Code:
import java.lang.StringBuilder;
public class test {
public static void main(String[] args) {
String text = "Add a dash before and after every vowel in the said string:";
System.out.println("Original string: "+text);
System.out.println("Reverse the words of length higher than 3 in the said string:\n"+validate(text));
text = "The quick brown fox jumps over the lazy dog.";
System.out.println("\nOriginal string: "+text);
System.out.println("Reverse the words of length higher than 3 in the said string:\n"+validate(text));
}
public static String validate(String text) {
String[] words = text.split(" ");
StringBuilder result_str = new StringBuilder();
for (String word : words) {
if (word.length() >= 4) {
result_str.append(new StringBuilder(word).reverse());
} else {
result_str.append(word);
}
result_str.append(" ");
}
return result_str.toString().trim();
}
}
Sample Output:
Original string: Add a dash before and after every vowel in the said string: Reverse the words of length higher than 3 in the said string: Add a hsad erofeb and retfa yreve lewov in the dias :gnirts Original string: The quick brown fox jumps over the lazy dog. Reverse the words of length higher than 3 in the said string: The kciuq nworb fox spmuj revo the yzal .god
Flowchart :
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