Java: Check whether every digit of a given integer is even

Java Method: Exercise-22 with Solution

Write a Java method to check whether every digit of a given integer is even. Return true if every digit is odd otherwise false.

Note: 1, 3, 5, 7, 9 are odd digits and 0, 2, 4, 6, and 8 are even digits

Sample data:
(8642)->true
(123)->false
(200)->true

Pictorial Presentation:

Sample Solution:

Java Code:

import java.util.Scanner;
public class Main { 
 public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);
        System.out.print("Input an integer:");
        int n = in.nextInt();
        System.out.print("Check whether every digit of the said integer is even or not!\n");
        System.out.print(test(n));
        }

  public static boolean test(int n){
    final int f = 10;
    if (n == 0){
        return false;
    }
    while(n != 0){
        if((n % f) % 2 != 0){
            return false;
        }
        n /= 10;
    }
     return true;
   }
}

Sample Output:

Input an integer: 8642
Check whether every digit of the said integer is even or not!
true

Flowchart :

Java Code Editor:

Contribute your code and comments through Disqus.

Previous Java Exercise: Display the factors of 3 in a given integer.
Next Java Exercise: Check all the characters in a string are vowels or not.