Java: Check whether an year (integer) entered by the user is a leap year or not

Last update on March 11 2025 11:09:07 (UTC/GMT +8 hours)

Check Leap Year

Write a Java method to check whether an year (integer) entered by the user is a leap year or not.

Pictorial Presentation:

Sample Solution:

Java Code:

import java.util.Scanner;

public class Exercise10 {
 
 public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);
        System.out.print("Input a year: ");
        int year = in.nextInt();

        System.out.println(is_LeapYear(year));
    }
 
 public static boolean is_LeapYear(int y)
    {
        boolean a = (y % 4) == 0;
        boolean b = (y % 100) != 0;
        boolean c = ((y % 100 == 0) && (y % 400 == 0));

        return a && (b || c);
    }
}

Sample Output:

Input a year: 2017                                                                                            
false

Flowchart:

For more Practice: Solve these Related Problems:

• Write a Java program to check if a year is a leap year and then determine the next leap year.
• Write a Java program to validate multiple years provided as a comma-separated string to check for leap years.
• Write a Java program to check if a year is a leap year using bitwise operations.
• Write a Java program to input a range of years and output all the leap years within that range.

Java Code Editor:

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