Java program to check if a number is a perfect square using lambda expression

Last update on December 21 2024 09:59:20 (UTC/GMT +8 hours)

Write a Java program to implement a lambda expression to check if a given number is a perfect square.

Note: A perfect square is an element of algebraic structure that is equal to the square of another element.

Sample Solution:

Java Code:

import java.util.function.Predicate;

public class Main {
  public static void main(String[] args) {
    // Define the perfect square check lambda expression
    Predicate < Integer > isPerfectSquare = n -> {
      int sqrt = (int) Math.sqrt(n);
      return sqrt * sqrt == n;
    };

    // Test the lambda expression with some numbers
    int N = 36;
    boolean result1 = isPerfectSquare.test(N);
    System.out.println(N + " is a perfect square? " + result1);

    N = 26;
    boolean result2 = isPerfectSquare.test(N);
    System.out.println(N + " is a perfect square? " + result2);

    N = 10000;
    boolean result3 = isPerfectSquare.test(N);
    System.out.println(N + " is a perfect square? " + result3);
  }
}

Sample Output:

36 is a perfect square? true
26 is a perfect square? false
10000 is a perfect square? true

Explanation:

In the above exercise,

• Import the Predicate functional interface.
• In the main method, we define the lambda expression isPerfectSquare, which takes an integer N.
• The lambda expression checks if the square of the square root of n is equal to n. If it is, then N is a perfect square.
• We test the lambda expression by calling the test method with different numbers.
• Finally, we print the results to the console.

Flowchart:

Live Demo:

Java Code Editor:

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