Java program to find length of longest and smallest string using lambda expression

Last update on December 21 2024 09:40:26 (UTC/GMT +8 hours)

Write a Java program to implement a lambda expression to find the length of the longest and smallest string in a list.

Sample Solution:

Java Code:

import java.util.Arrays;
import java.util.List;

public class Main {
  public static void main(String[] args) {
    // Create a list of colors
    List < String > colors = Arrays.asList("Red", "Green", "Blue", "Orange", "Black");

    // Print the elements of the list
    System.out.println("Elements of the list: " + colors);

    // Find the length of the longest string using lambda expression
    int max_length = colors.stream()
      .mapToInt(String::length)
      .max()
      .orElse(0);
    // Print the length of the longest string
    System.out.println("Length of the longest string: " + max_length);

    // Find the length of the smallest string using lambda expression
    int min_length = colors.stream()
      .mapToInt(String::length)
      .min()
      .orElse(0);
    // Print the length of the smallest string
    System.out.println("Length of the smallest string: " + min_length);
  }
}

Sample Output:

Elements of the list: [Red, Green, Blue, Orange, Black]
Length of the longest string: 6
Length of the smallest string: 3

Explanation:

In the above exercise,

• Import the necessary classes: Arrays and List.
• In the main method, we create a list of colors called colors using Arrays.asList().
• Use the stream() method on the colors list to create a stream of strings.
• Use the mapToInt() method to map each string to its integer length.
• The max() method is used to get the maximum length of a stream of integers.
• The min() method is used to get the minimum length among a stream of integers.
• The orElse() method is used to provide a default value of 0 in case the stream is empty.
• Finally, we print the length of the longest and smallest string.

Flowchart:

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