Java: Program than read an integer and calculate the sum of its digits and write the number of each digit of the sum in English
Digit Sum in Words
Write a Java program that then reads an integer and calculates the sum of its digits and writes the number of each digit of the sum in English.
Sample Solution:
Java Code:
import java.io.*;
public class Main {
public static void main(String[] args) {
// Create a BufferedReader to read input from the user
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
try {
int sum = 0;
// Read a line of text from the user
String str = br.readLine();
char[] numStr = str.toCharArray();
// Calculate the sum of the digits in the input number
for (int i = 0; i < numStr.length; i++) {
sum += numStr[i] - '0';
}
// Print the original number and call the print_number function
System.out.println("Original Number: " + str);
print_number(sum);
} catch (IOException e) {
e.printStackTrace();
}
}
public static void print_number(int n) {
int x;
int y;
int z;
String[] number = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
// Print the sum of the digits of the number
System.out.println("Sum of the digits of the said number: " + n);
if (n < 10) {
// If the number is less than 10, print the corresponding word
System.out.println(number[n]);
} else if (n < 100) {
// If the number is less than 100, split it into tens and ones
x = n / 10;
y = n - x * 10;
System.out.println("In English: " + number[x] + " " + number[y]);
} else {
// If the number is three digits, split it into hundreds, tens, and ones
x = n / 100;
y = (n - x * 100) / 10;
z = n - x * 100 - y * 10;
System.out.println("In English: " + number[x] + " " + number[y] + " " + number[z]);
}
}
}
If input 8
Sample Output:
Original Number: 8 Sum of the digits of the said number: 8 eight
Flowchart:
Java Code Editor:
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