Java: Plus one to the number of a specified positive numbers represented as an array of digits
Add One to Array Number
Write a Java program to add one to a positive number represented as an array of digits.
Sample array: [9, 9, 9, 9] which represents 9999
Output: [1, 0, 0, 0, 0].
Sample Solution:
Java Code:
// Importing necessary Java utilities
import java.util.*;
// Main class Solution
public class Solution {
// Main method
public static void main(String[] args) {
// Initializing an array of integers
int[] nums = {9, 9, 9, 9};
// Printing the original array
System.out.println("Original array: " + Arrays.toString(nums));
// Printing the array of digits after adding one to the input array
System.out.println("Array of digits: " + Arrays.toString(plus_One_digit(nums)));
}
// Method to add one to the last digit of the input array
public static int[] plus_One_digit(int[] digits_nums) {
// Looping through the array from the end to the start
for (int i = digits_nums.length - 1; i > -1; --i) {
// Checking if the digit is not 9
if (digits_nums[i] != 9) {
digits_nums[i] += 1; // Incrementing the digit by 1
// Setting the digits after the incremented digit to 0
for (int j = i + 1; j < digits_nums.length; ++j) {
digits_nums[j] = 0;
}
return digits_nums; // Returning the updated array
}
}
// If all digits are 9, creating a new array with an additional digit for carrying over 1
int[] result = new int[digits_nums.length + 1];
result[0] = 1; // Setting the first digit to 1
return result; // Returning the new array with the carried over 1
}
}
Sample Output:
Original array: [9, 9, 9, 9] Array of digits: [1, 0, 0, 0, 0]
Flowchart:
Java Code Editor:
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