Java: Find the index of the first unique character in a given string
First Unique Character Index
Write a Java program to find the index of the first unique character in a given string. Assume that there is at least one unique character in the string.
Pictorial Presentation:
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Sample Solution:
Java Code:
import java.util.*;
public class Solution {
public static void main(String[] args) {
// Test the first_Uniq_Char function and print the result
String s = "wresource";
System.out.println("Original String: " + s);
System.out.println("First unique character of the above: " + first_Uniq_Char(s));
}
public static int first_Uniq_Char(String s) {
int[] freq = new int[256]; // Create an array to store character frequencies (assuming ASCII characters)
// Count the frequency of each character in the string
for (char c : s.toCharArray()) {
freq[c - 'a']++; // Increment the count at the corresponding index in the array
}
// Iterate through the string to find the index of the first unique character
for (int i = 0; i < s.length(); i++) {
if (freq[s.charAt(i) - 'a'] == 1) {
return i; // Return the index of the first character with a frequency of 1
}
}
return -1; // Return -1 if there are no unique characters
}
}
Sample Output:
Original String: wresource First unique character of the above: 0
Flowchart:
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For more Practice: Solve these Related Problems:
- Write a Java program to find the index of the first non-repeating vowel in a given string.
- Write a Java program to find the index of the last unique character in a given string.
- Write a Java program to return a list of all unique characters in a given string along with their indices.
- Write a Java program to find the index of the first unique character in a string while ignoring case sensitivity.
Java Code Editor:
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