Java: Iterating on two integers to get Fizz, Buzz and FizzBuzz
FizzBuzz 1 to 100
Write a Java program that iterates integers from 1 to 100. For multiples of three print "Fizz" instead of the number and print "Buzz" for five. When the number is divided by three and five, print "fizz buzz".
Sample Solution:
Java Code:
import java.util.*;
public class Exercise116 {
public static void main(String[] args) {
// Iterate from 1 to 100
for (int i = 1; i <= 100; i++) {
if (i % 3 == 0 && i % 5 == 0) {
// Check if the number is divisible by both 3 and 5 (fizz buzz)
System.out.printf("\n%d: fizz buzz", i);
} else if (i % 5 == 0) {
// Check if the number is divisible by 5 (buzz)
System.out.printf("\n%d: buzz", i);
} else if (i % 3 == 0) {
// Check if the number is divisible by 3 (fizz)
System.out.printf("\n%d: fizz", i);
}
}
System.out.printf("\n");
}
}
Sample Output:
3: fizz 5: buzz 6: fizz 9: fizz 10: buzz 12: fizz 15: fizz buzz 18: fizz 20: buzz 21: fizz 24: fizz 25: buzz 27: fizz 30: fizz buzz 33: fizz 35: buzz 36: fizz 39: fizz 40: buzz 42: fizz 45: fizz buzz 48: fizz 48: fizz 50: buzz 51: fizz 54: fizz 55: buzz 57: fizz 60: fizz buzz 63: fizz 65: buzz 66: fizz 69: fizz 70: buzz 72: fizz 75: fizz buzz 78: fizz 80: buzz 81: fizz 84: fizz 85: buzz 87: fizz 90: fizz buzz 93: fizz 95: buzz 96: fizz 99: fizz 100: buzz
Flowchart:
For more Practice: Solve these Related Problems:
- Modify the program to print "Fizz" for numbers divisible by 4 and "Buzz" for 6.
- Write a program to return a list of all "Fizz" numbers.
- Modify the program to allow custom words for different divisibility conditions.
- Write a program to count how many times "Fizz" and "Buzz" appear.
Go to:
PREV : Check Palindrome Number.
NEXT : Square Root Calculation.
Java Code Editor:
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