Java: Create a new array from a given array of integers, new array will contain the elements from the given array before the last element value 10
Array Before Last 10
Write a Java program to create an array from a given array of integers. The newly created array will contain the elements from the given array before the last element value of 10.
Pictorial Presentation:
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Sample Solution:
Java Code:
import java.util.*;
public class Exercise104 {
public static void main(String[] args) {
int[] array_nums = {11, 15, 13, 10, 45, 20, 33, 53};
int result = 0;
System.out.println("Original Array: "+Arrays.toString(array_nums));
int l = 0;
int[] new_array;
// Find the first occurrence of 10 in the array
while(array_nums[l] != 10)
l++;
// Create a new array with elements before the first occurrence of 10
new_array = new int[l];
for(int i = 0; i < l; i++)
new_array[i] = array_nums[i];
System.out.println("New Array: "+Arrays.toString(new_array));
}
}
Sample Output:
Original Array: [11, 15, 13, 10, 45, 20, 33, 53] New Array: [11, 15, 13]
Flowchart:
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For more Practice: Solve these Related Problems:
- Modify the program to return elements before the first occurrence of 10.
- Write a program to return elements before the second-last occurrence of 10.
- Modify the program to return the array including the last 10 itself.
- Write a program to handle cases where 10 does not exist in the array.
Java Code Editor:
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