Java: Create a new array from a given array of integers, new array will contain the elements from the given array after the last element value 10

Last update on May 12 2025 13:11:25 (UTC/GMT +8 hours)

Array After Last 10

Write a Java program to create an array from a given array of integers. The newly created array will contain elements from the given array after the last element value is 10.

Pictorial Presentation:

Sample Solution:

Java Code:

import java.util.*;

public class Exercise103 {
    public static void main(String[] args) {
        int[] array_nums = {11, 10, 13, 10, 45, 20, 33, 53};
        int result = 0; 
        System.out.println("Original Array: "+Arrays.toString(array_nums)); 

        int l = array_nums.length - 1;
        int[] new_array;

        // Find the last occurrence of 10 in the array
        while(array_nums[l] != 10)
            l--;

        // Create a new array with elements after the last 10
        new_array = new int[array_nums.length - 1 - l];
        for(int i = l + 1; i < array_nums.length; i++)
            new_array[i - l - 1] = array_nums[i];

        System.out.println("New Array: "+Arrays.toString(new_array)); 
    }
}

Sample Output:

Original Array: [11, 10, 13, 10, 45, 20, 33, 53]                       
New Array: [45, 20, 33, 53]

Flowchart:

For more Practice: Solve these Related Problems:

• Modify the program to return elements after the last occurrence of any given number.
• Write a program to return elements after the second-last occurrence of 10.
• Modify the program to return the array excluding the last 10 itself.
• Write a program to check if 10 exists in the array before creating the new array.

Go to:

• Java Basic Programming Exercises Home ↩
• Java Exercises Home ↩

PREV : Contains 10 or 30.
NEXT : Array Before Last 10.

Java Code Editor: